Hi, I'm Maryia Huchkova; I'm beginner front-end;

{Code example}

Given an array of integers, find the one that appears an odd number of times. There will always be only one integer that appears an odd number of times.

[1,2,2,3,3,3,4,3,3,3,2,2,1] should return 4, because it appears 1 time (which is odd).

                    
function findOdd(numbers) {
    const counters = new Map();
    for (const number of numbers) {
        if (counters.has(number)) {
            let counter = counters.get(number);
            counter++;
            counters.set(number, counter);
        } else {
            counters.set(number, 1);
        }
    }
    for (const number of counters.keys()) {
        let counter = counters.get(number);
        if (counter % 2 === 1) {
            return number;
        }
    }
}               
                    
                

Write a function toWeirdCase (weirdcase in Ruby) that accepts a string, and returns the same string with all even indexed characters in each word upper cased, and all odd indexed characters in each word lower cased. The zero-ith index is even and you need to start over for each word.

toWeirdCase( "Weird string case" ); // => returns "WeIrD StRiNg CaSe"

                    
function toWeirdCase(string){
    let words = [];
    let newStr = "";
    words = string.split(" ");
    for (let word of words) {
        for (let i = 0; i < word.length; i++) {
            if (i % 2 === 0) {
                newStr += word[i].toString().toUpperCase();
            } else {
                newStr += word[i].toString();
            }
            if (i === word.length - 1) {
                newStr += " ";
            }
        }
    }
    return newStr.trim();
}                        
                    
                

Given a lottery ticket (ticket), represented by an array of 2-value arrays, you must find out if you've won the jackpot. To do this, you must first count the 'mini-wins' on your ticket. Each subarray has both a string and a number within it. If the character code of any of the characters in the string matches the number, you get a mini win. Note you can only have one mini win per sub array.

bingo([['ABC', 65], ['HGR', 74], ['BYHT', 74]], 1); // => 'Winner!'

                    
function bingo(ticket, win) {
    let countWin = 0;
    for (let i = 0; i < ticket.length; i++) {
        let str = "";
        str = ticket[i][0];
        for (let j = 0; j < str.length; j++) {
            if (str.charCodeAt(j) == ticket[i][1]) {
                countWin += 1;
                break;
            }
        }
    }
    if (countWin >= win) {
        return "Winner!";
    } else {
        return "Loser!";
    }
}